5c^2(c-5)+(6c+7)(3c-2)=0

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Solution for 5c^2(c-5)+(6c+7)(3c-2)=0 equation: 


Simplifying
5c2(c + -5) + (6c + 7)(3c + -2) = 0

Reorder the terms:
5c2(-5 + c) + (6c + 7)(3c + -2) = 0
(-5 * 5c2 + c * 5c2) + (6c + 7)(3c + -2) = 0
(-25c2 + 5c3) + (6c + 7)(3c + -2) = 0

Reorder the terms:
-25c2 + 5c3 + (7 + 6c)(3c + -2) = 0

Reorder the terms:
-25c2 + 5c3 + (7 + 6c)(-2 + 3c) = 0

Multiply (7 + 6c) * (-2 + 3c)
-25c2 + 5c3 + (7(-2 + 3c) + 6c * (-2 + 3c)) = 0
-25c2 + 5c3 + ((-2 * 7 + 3c * 7) + 6c * (-2 + 3c)) = 0
-25c2 + 5c3 + ((-14 + 21c) + 6c * (-2 + 3c)) = 0
-25c2 + 5c3 + (-14 + 21c + (-2 * 6c + 3c * 6c)) = 0
-25c2 + 5c3 + (-14 + 21c + (-12c + 18c2)) = 0

Combine like terms: 21c + -12c = 9c
-25c2 + 5c3 + (-14 + 9c + 18c2) = 0

Reorder the terms:
-14 + 9c + -25c2 + 18c2 + 5c3 = 0

Combine like terms: -25c2 + 18c2 = -7c2
-14 + 9c + -7c2 + 5c3 = 0

Solving
-14 + 9c + -7c2 + 5c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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